<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom">
  <channel>
    <title>Retired on Zero&#39;s Blog</title>
    <link>/tags/retired/</link>
    <description>Recent content in Retired on Zero&#39;s Blog</description>
    <generator>Hugo</generator>
    <language>en-us</language>
    <lastBuildDate>Fri, 27 Feb 2026 09:58:00 +0700</lastBuildDate>
    <atom:link href="/tags/retired/index.xml" rel="self" type="application/rss+xml" />
    <item>
      <title>HTB - Crypto: quick maffs</title>
      <link>/posts/htb-crypto-quick-maffs/</link>
      <pubDate>Fri, 27 Feb 2026 09:58:00 +0700</pubDate>
      <guid>/posts/htb-crypto-quick-maffs/</guid>
      <description>&lt;h2 id=&#34;challenge-summary&#34;&gt;Challenge Summary&lt;/h2&gt;&#xA;&lt;ul&gt;&#xA;&lt;li&gt;&lt;strong&gt;Name:&lt;/strong&gt; quick maffs&lt;/li&gt;&#xA;&lt;li&gt;&lt;strong&gt;Category:&lt;/strong&gt; Crypto&lt;/li&gt;&#xA;&lt;li&gt;&lt;strong&gt;Difficulty:&lt;/strong&gt; Hard&lt;/li&gt;&#xA;&lt;li&gt;&lt;strong&gt;Goal:&lt;/strong&gt; Recover the plaintext triplet and reconstruct the flag.&lt;/li&gt;&#xA;&lt;/ul&gt;&#xA;&lt;h2 id=&#34;root-cause&#34;&gt;Root Cause&lt;/h2&gt;&#xA;&lt;p&gt;The service encrypts three related plaintext chunks under the same RSA modulus/exponent pair:&lt;/p&gt;&#xA;&lt;ul&gt;&#xA;&lt;li&gt;&lt;code&gt;c1 = m1^e mod N&lt;/code&gt;&lt;/li&gt;&#xA;&lt;li&gt;&lt;code&gt;c2 = m2^e mod N&lt;/code&gt;&lt;/li&gt;&#xA;&lt;li&gt;&lt;code&gt;c3 = m3^e mod N&lt;/code&gt;&lt;/li&gt;&#xA;&lt;li&gt;and leaks &lt;code&gt;m1 + m2 + m3 = hint&lt;/code&gt;&lt;/li&gt;&#xA;&lt;/ul&gt;&#xA;&lt;p&gt;Because &lt;code&gt;e&lt;/code&gt; is a prime &lt;code&gt;&amp;lt; 1024&lt;/code&gt;, we can iterate candidate exponents and solve the algebraic system directly.&lt;/p&gt;</description>
    </item>
  </channel>
</rss>
